Base | Representation |
---|---|
bin | 11111010110011111111… |
… | …101011010000010000011 |
3 | 21121222001011220012000112 |
4 | 133112133331122002003 |
5 | 240244314321240201 |
6 | 4325425111541535 |
7 | 311440404210221 |
oct | 37263775320203 |
9 | 7558034805015 |
10 | 2154462290051 |
11 | 76077a883555 |
12 | 2a967108a8ab |
13 | 12821b445c36 |
14 | 763c2b31b11 |
15 | 3b0986ec0bb |
hex | 1f59ff5a083 |
2154462290051 has 2 divisors, whose sum is σ = 2154462290052. Its totient is φ = 2154462290050.
The previous prime is 2154462290027. The next prime is 2154462290069. The reversal of 2154462290051 is 1500922644512.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2154462290051 - 226 = 2154395181187 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2154462289990 and 2154462290008.
It is not a weakly prime, because it can be changed into another prime (2154462280051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1077231145025 + 1077231145026.
It is an arithmetic number, because the mean of its divisors is an integer number (1077231145026).
Almost surely, 22154462290051 is an apocalyptic number.
2154462290051 is a deficient number, since it is larger than the sum of its proper divisors (1).
2154462290051 is an equidigital number, since it uses as much as digits as its factorization.
2154462290051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 172800, while the sum is 41.
The spelling of 2154462290051 in words is "two trillion, one hundred fifty-four billion, four hundred sixty-two million, two hundred ninety thousand, fifty-one".
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