Base | Representation |
---|---|
bin | 110000111111111100100001… |
… | …111011000010000110101011 |
3 | 1001021000122121002010121211222 |
4 | 300333330201323002012223 |
5 | 211221230113104400133 |
6 | 2042155330515212255 |
7 | 63251254413514016 |
oct | 6077744173020653 |
9 | 1037018532117758 |
10 | 215500553200043 |
11 | 627352a9214741 |
12 | 2020554b2a708b |
13 | 93327cc11a317 |
14 | 3b303d4da237d |
15 | 19da9e5bace98 |
hex | c3ff21ec21ab |
215500553200043 has 2 divisors, whose sum is σ = 215500553200044. Its totient is φ = 215500553200042.
The previous prime is 215500553199947. The next prime is 215500553200061. The reversal of 215500553200043 is 340002355005512.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 215500553200043 - 218 = 215500552937899 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 215500553199976 and 215500553200012.
It is not a weakly prime, because it can be changed into another prime (215500553200073) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107750276600021 + 107750276600022.
It is an arithmetic number, because the mean of its divisors is an integer number (107750276600022).
Almost surely, 2215500553200043 is an apocalyptic number.
215500553200043 is a deficient number, since it is larger than the sum of its proper divisors (1).
215500553200043 is an equidigital number, since it uses as much as digits as its factorization.
215500553200043 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 90000, while the sum is 35.
The spelling of 215500553200043 in words is "two hundred fifteen trillion, five hundred billion, five hundred fifty-three million, two hundred thousand, forty-three".
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