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21550500505555 = 571427894312157
BaseRepresentation
bin1001110011001100111011…
…11011010110011111010011
32211022012121102201010112221
410321212131323112133103
510311040411112134210
6113500055133001511
74352654330614030
oct471463573263723
984265542633487
1021550500505555
11695957479572a
12250076b023297
13c0428506b298
1454709a8a2387
152758a09dd1da
hex13999ded67d3

21550500505555 has 16 divisors (see below), whose sum is σ = 29555185959360. Its totient is φ = 14777379142272.

The previous prime is 21550500505549. The next prime is 21550500505561. The reversal of 21550500505555 is 55550500505512.

It is an interprime number because it is at equal distance from previous prime (21550500505549) and next prime (21550500505561).

It is a cyclic number.

It is not a de Polignac number, because 21550500505555 - 213 = 21550500497363 is a prime.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2841537 + ... + 7153693.

It is an arithmetic number, because the mean of its divisors is an integer number (1847199122460).

Almost surely, 221550500505555 is an apocalyptic number.

21550500505555 is a deficient number, since it is larger than the sum of its proper divisors (8004685453805).

21550500505555 is a wasteful number, since it uses less digits than its factorization.

21550500505555 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4454958.

The product of its (nonzero) digits is 781250, while the sum is 43.

Subtracting from 21550500505555 its sum of digits (43), we obtain a palindrome (21550500505512).

The spelling of 21550500505555 in words is "twenty-one trillion, five hundred fifty billion, five hundred million, five hundred five thousand, five hundred fifty-five".

Divisors: 1 5 7 35 142789 713945 999523 4312157 4997615 21560785 30185099 150925495 615728585873 3078642929365 4310100101111 21550500505555