Base | Representation |
---|---|
bin | 1001110011001101111001… |
… | …00011000110111010111111 |
3 | 2211022020221020101202020220 |
4 | 10321212330203012322333 |
5 | 10311042434121302111 |
6 | 113500222124112423 |
7 | 4353003136410606 |
oct | 471467443067277 |
9 | 84266836352226 |
10 | 21551014244031 |
11 | 6959808785a88 |
12 | 2500893095713 |
13 | c0433762374c |
14 | 547108bd2a3d |
15 | 2758d0b6be06 |
hex | 1399bc8c6ebf |
21551014244031 has 16 divisors (see below), whose sum is σ = 28766634946560. Its totient is φ = 14351374252800.
The previous prime is 21551014243999. The next prime is 21551014244047. The reversal of 21551014244031 is 13044241015512.
It is not a de Polignac number, because 21551014244031 - 25 = 21551014243999 is a prime.
It is a super-2 number, since 2×215510142440312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 21551014243983 and 21551014244001.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (21551014244231) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 13501656 + ... + 15013218.
It is an arithmetic number, because the mean of its divisors is an integer number (1797914684160).
Almost surely, 221551014244031 is an apocalyptic number.
21551014244031 is a deficient number, since it is larger than the sum of its proper divisors (7215620702529).
21551014244031 is a wasteful number, since it uses less digits than its factorization.
21551014244031 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1516846.
The product of its (nonzero) digits is 19200, while the sum is 33.
Adding to 21551014244031 its reverse (13044241015512), we get a palindrome (34595255259543).
The spelling of 21551014244031 in words is "twenty-one trillion, five hundred fifty-one billion, fourteen million, two hundred forty-four thousand, thirty-one".
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