Base | Representation |
---|---|
bin | 1001110011010000010100… |
… | …11001111000111001001011 |
3 | 2211022101022021020220011022 |
4 | 10321220022121320321023 |
5 | 10311103123013400443 |
6 | 113500555504423055 |
7 | 4353050410106621 |
oct | 471501231707113 |
9 | 84271267226138 |
10 | 21552320450123 |
11 | 695a319031a51 |
12 | 2500b98617a8b |
13 | c044b5122468 |
14 | 5471d048b511 |
15 | 27595a685e68 |
hex | 139a0a678e4b |
21552320450123 has 2 divisors, whose sum is σ = 21552320450124. Its totient is φ = 21552320450122.
The previous prime is 21552320450099. The next prime is 21552320450183. The reversal of 21552320450123 is 32105402325512.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 21552320450123 - 222 = 21552316255819 is a prime.
It is a super-3 number, since 3×215523204501233 (a number of 41 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (21552320450183) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10776160225061 + 10776160225062.
It is an arithmetic number, because the mean of its divisors is an integer number (10776160225062).
Almost surely, 221552320450123 is an apocalyptic number.
21552320450123 is a deficient number, since it is larger than the sum of its proper divisors (1).
21552320450123 is an equidigital number, since it uses as much as digits as its factorization.
21552320450123 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72000, while the sum is 35.
Adding to 21552320450123 its reverse (32105402325512), we get a palindrome (53657722775635).
The spelling of 21552320450123 in words is "twenty-one trillion, five hundred fifty-two billion, three hundred twenty million, four hundred fifty thousand, one hundred twenty-three".
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