Base | Representation |
---|---|
bin | 1100100010111010011… |
… | …0001111011010000001 |
3 | 202121022122222121100102 |
4 | 3020232212033122001 |
5 | 12012401204010223 |
6 | 243002502532145 |
7 | 21400015654634 |
oct | 3105646173201 |
9 | 677278877312 |
10 | 215530141313 |
11 | 83451167233 |
12 | 35930737055 |
13 | 1742a9446c6 |
14 | a6088a5c1b |
15 | 5916aa7928 |
hex | 322e98f681 |
215530141313 has 2 divisors, whose sum is σ = 215530141314. Its totient is φ = 215530141312.
The previous prime is 215530141301. The next prime is 215530141349. The reversal of 215530141313 is 313141035512.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 189810962929 + 25719178384 = 435673^2 + 160372^2 .
It is a cyclic number.
It is not a de Polignac number, because 215530141313 - 210 = 215530140289 is a prime.
It is not a weakly prime, because it can be changed into another prime (215530141213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107765070656 + 107765070657.
It is an arithmetic number, because the mean of its divisors is an integer number (107765070657).
Almost surely, 2215530141313 is an apocalyptic number.
It is an amenable number.
215530141313 is a deficient number, since it is larger than the sum of its proper divisors (1).
215530141313 is an equidigital number, since it uses as much as digits as its factorization.
215530141313 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5400, while the sum is 29.
Adding to 215530141313 its reverse (313141035512), we get a palindrome (528671176825).
The spelling of 215530141313 in words is "two hundred fifteen billion, five hundred thirty million, one hundred forty-one thousand, three hundred thirteen".
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