Base | Representation |
---|---|
bin | 11111010111010011111… |
… | …010111000001000000011 |
3 | 21122001021221020210001000 |
4 | 133113103322320020003 |
5 | 240303111003321430 |
6 | 4330051412343043 |
7 | 311501121035352 |
oct | 37272372701003 |
9 | 7561257223030 |
10 | 2155334042115 |
11 | 761087971801 |
12 | 2a9875014a83 |
13 | 128329c2bc67 |
14 | 76466817999 |
15 | 3b0e9ee8e60 |
hex | 1f5d3eb8203 |
2155334042115 has 32 divisors (see below), whose sum is σ = 3836044592640. Its totient is φ = 1148209600608.
The previous prime is 2155334042041. The next prime is 2155334042119. The reversal of 2155334042115 is 5112404335512.
2155334042115 is a `hidden beast` number, since 2 + 1 + 5 + 5 + 33 + 404 + 211 + 5 = 666.
It is not a de Polignac number, because 2155334042115 - 29 = 2155334041603 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 2155334042115.
It is not an unprimeable number, because it can be changed into a prime (2155334042119) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 8921247 + ... + 9159656.
It is an arithmetic number, because the mean of its divisors is an integer number (119876393520).
Almost surely, 22155334042115 is an apocalyptic number.
2155334042115 is a deficient number, since it is larger than the sum of its proper divisors (1680710550525).
2155334042115 is a wasteful number, since it uses less digits than its factorization.
2155334042115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18081800 (or 18081794 counting only the distinct ones).
The product of its (nonzero) digits is 72000, while the sum is 36.
Adding to 2155334042115 its reverse (5112404335512), we get a palindrome (7267738377627).
The spelling of 2155334042115 in words is "two trillion, one hundred fifty-five billion, three hundred thirty-four million, forty-two thousand, one hundred fifteen".
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