Base | Representation |
---|---|
bin | 11111010111011001111… |
… | …001011010001001100011 |
3 | 21122001112220221110002122 |
4 | 133113121321122021203 |
5 | 240303312141223413 |
6 | 4330105353534455 |
7 | 311503446300203 |
oct | 37273171321143 |
9 | 7561486843078 |
10 | 2155434320483 |
11 | 761129533394 |
12 | 2a98a271442b |
13 | 12834493c382 |
14 | 76475c7c403 |
15 | 3b103c06108 |
hex | 1f5d9e5a263 |
2155434320483 has 2 divisors, whose sum is σ = 2155434320484. Its totient is φ = 2155434320482.
The previous prime is 2155434320461. The next prime is 2155434320581. The reversal of 2155434320483 is 3840234345512.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2155434320483 - 218 = 2155434058339 is a prime.
It is not a weakly prime, because it can be changed into another prime (2155434320443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1077717160241 + 1077717160242.
It is an arithmetic number, because the mean of its divisors is an integer number (1077717160242).
Almost surely, 22155434320483 is an apocalyptic number.
2155434320483 is a deficient number, since it is larger than the sum of its proper divisors (1).
2155434320483 is an equidigital number, since it uses as much as digits as its factorization.
2155434320483 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1382400, while the sum is 44.
Adding to 2155434320483 its reverse (3840234345512), we get a palindrome (5995668665995).
The spelling of 2155434320483 in words is "two trillion, one hundred fifty-five billion, four hundred thirty-four million, three hundred twenty thousand, four hundred eighty-three".
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