Base | Representation |
---|---|
bin | 11111011000011010010… |
… | …000100110010000011011 |
3 | 21122011100011211000122221 |
4 | 133120122100212100123 |
5 | 240313020110004321 |
6 | 4330404450124511 |
7 | 311542300516453 |
oct | 37303220462033 |
9 | 7564304730587 |
10 | 2156514141211 |
11 | 761633015711 |
12 | 2a9b44280737 |
13 | 128487576151 |
14 | 76539446d63 |
15 | 3b168902e41 |
hex | 1f61a42641b |
2156514141211 has 4 divisors (see below), whose sum is σ = 2157464568400. Its totient is φ = 2155563714024.
The previous prime is 2156514141193. The next prime is 2156514141227. The reversal of 2156514141211 is 1121414156512.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2156514141211 - 225 = 2156480586779 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2156514141281) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 475210191 + ... + 475214728.
It is an arithmetic number, because the mean of its divisors is an integer number (539366142100).
Almost surely, 22156514141211 is an apocalyptic number.
2156514141211 is a deficient number, since it is larger than the sum of its proper divisors (950427189).
2156514141211 is an equidigital number, since it uses as much as digits as its factorization.
2156514141211 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 950427188.
The product of its digits is 9600, while the sum is 34.
Adding to 2156514141211 its reverse (1121414156512), we get a palindrome (3277928297723).
The spelling of 2156514141211 in words is "two trillion, one hundred fifty-six billion, five hundred fourteen million, one hundred forty-one thousand, two hundred eleven".
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