Base | Representation |
---|---|
bin | 11111011001101011101… |
… | …101100000111000000011 |
3 | 21122021212102012011202201 |
4 | 133121223231200320003 |
5 | 240323314423111333 |
6 | 4331152223454031 |
7 | 311621203051444 |
oct | 37315355407003 |
9 | 7567772164681 |
10 | 2157880675843 |
11 | 762174427382 |
12 | 2aa265a57317 |
13 | 128644708519 |
14 | 76628b272cb |
15 | 3b1e888717d |
hex | 1f66bb60e03 |
2157880675843 has 2 divisors, whose sum is σ = 2157880675844. Its totient is φ = 2157880675842.
The previous prime is 2157880675789. The next prime is 2157880675859. The reversal of 2157880675843 is 3485760887512.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2157880675843 is a prime.
It is a super-2 number, since 2×21578806758432 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2157880675343) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1078940337921 + 1078940337922.
It is an arithmetic number, because the mean of its divisors is an integer number (1078940337922).
Almost surely, 22157880675843 is an apocalyptic number.
2157880675843 is a deficient number, since it is larger than the sum of its proper divisors (1).
2157880675843 is an equidigital number, since it uses as much as digits as its factorization.
2157880675843 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 90316800, while the sum is 64.
The spelling of 2157880675843 in words is "two trillion, one hundred fifty-seven billion, eight hundred eighty million, six hundred seventy-five thousand, eight hundred forty-three".
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