Base | Representation |
---|---|
bin | 1001110100101000000010… |
… | …01100001001010110000001 |
3 | 2211110212212001110220210001 |
4 | 10322110001030021112001 |
5 | 10312341043041232201 |
6 | 113534344315440001 |
7 | 4356335345631031 |
oct | 472240114112601 |
9 | 84425761426701 |
10 | 21599410492801 |
11 | 6978293144a99 |
12 | 250a13aa56001 |
13 | c08a7b04613b |
14 | 5495ba5338c1 |
15 | 276cb4821301 |
hex | 13a501309581 |
21599410492801 has 4 divisors (see below), whose sum is σ = 21599423028400. Its totient is φ = 21599397957204.
The previous prime is 21599410492711. The next prime is 21599410492831. The reversal of 21599410492801 is 10829401499512.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-21599410492801 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (21599410492831) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3174291 + ... + 7298968.
It is an arithmetic number, because the mean of its divisors is an integer number (5399855757100).
Almost surely, 221599410492801 is an apocalyptic number.
It is an amenable number.
21599410492801 is a deficient number, since it is larger than the sum of its proper divisors (12535599).
21599410492801 is a wasteful number, since it uses less digits than its factorization.
21599410492801 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12535598.
The product of its (nonzero) digits is 1866240, while the sum is 55.
The spelling of 21599410492801 in words is "twenty-one trillion, five hundred ninety-nine billion, four hundred ten million, four hundred ninety-two thousand, eight hundred one".
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