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21611305022147 is a prime number
BaseRepresentation
bin1001110100111110001100…
…01010001011001011000011
32211112000120000010121120222
410322133012022023023003
510313034423041202042
6113544032500453255
74360236166516121
oct472370612131303
984460500117528
1021611305022147
116982337308a35
1225104ba3aa22b
13c09c253a0099
14549dc8138911
1527725dbab2d2
hex13a7c628b2c3

21611305022147 has 2 divisors, whose sum is σ = 21611305022148. Its totient is φ = 21611305022146.

The previous prime is 21611305022143. The next prime is 21611305022243. The reversal of 21611305022147 is 74122050311612.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 21611305022147 - 22 = 21611305022143 is a prime.

It is a super-2 number, since 2×216113050221472 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (21611305022143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10805652511073 + 10805652511074.

It is an arithmetic number, because the mean of its divisors is an integer number (10805652511074).

Almost surely, 221611305022147 is an apocalyptic number.

21611305022147 is a deficient number, since it is larger than the sum of its proper divisors (1).

21611305022147 is an equidigital number, since it uses as much as digits as its factorization.

21611305022147 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 20160, while the sum is 35.

Adding to 21611305022147 its reverse (74122050311612), we get a palindrome (95733355333759).

The spelling of 21611305022147 in words is "twenty-one trillion, six hundred eleven billion, three hundred five million, twenty-two thousand, one hundred forty-seven".