Base | Representation |
---|---|
bin | 1001110101010110001000… |
… | …01010110010010111010011 |
3 | 2211120020201122111212022011 |
4 | 10322223010022302113103 |
5 | 10313242233032431011 |
6 | 113554000025123351 |
7 | 4361202520524331 |
oct | 472530412622723 |
9 | 84506648455264 |
10 | 21624156530131 |
11 | 6987831691111 |
12 | 2512aa6329557 |
13 | c0b1c2a8038c |
14 | 54a886c8cb51 |
15 | 27776207a621 |
hex | 13aac42b25d3 |
21624156530131 has 2 divisors, whose sum is σ = 21624156530132. Its totient is φ = 21624156530130.
The previous prime is 21624156530069. The next prime is 21624156530161. The reversal of 21624156530131 is 13103565142612.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 21624156530131 - 223 = 21624148141523 is a prime.
It is a super-2 number, since 2×216241565301312 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (21624156530161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10812078265065 + 10812078265066.
It is an arithmetic number, because the mean of its divisors is an integer number (10812078265066).
Almost surely, 221624156530131 is an apocalyptic number.
21624156530131 is a deficient number, since it is larger than the sum of its proper divisors (1).
21624156530131 is an equidigital number, since it uses as much as digits as its factorization.
21624156530131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 129600, while the sum is 40.
The spelling of 21624156530131 in words is "twenty-one trillion, six hundred twenty-four billion, one hundred fifty-six million, five hundred thirty thousand, one hundred thirty-one".
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