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2163441414113 = 7620994976941
BaseRepresentation
bin11111011110110111001…
…010000010111111100001
321122211012221200221121222
4133132313022002333201
5240421212000222423
64333512105424425
7312206044413410
oct37366712027741
97584187627558
102163441414113
11764568306341
122ab35819b115
1312901c7971b5
14769d5471477
153b421b533c8
hex1f7b7282fe1

2163441414113 has 8 divisors (see below), whose sum is σ = 2472544785600. Its totient is φ = 1854348120720.

The previous prime is 2163441414109. The next prime is 2163441414131. The reversal of 2163441414113 is 3114141443612.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 2163441414113 - 22 = 2163441414109 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2163441414313) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2053778 + ... + 2923163.

It is an arithmetic number, because the mean of its divisors is an integer number (309068098200).

Almost surely, 22163441414113 is an apocalyptic number.

It is an amenable number.

2163441414113 is a deficient number, since it is larger than the sum of its proper divisors (309103371487).

2163441414113 is an equidigital number, since it uses as much as digits as its factorization.

2163441414113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5039047.

The product of its digits is 27648, while the sum is 35.

Adding to 2163441414113 its reverse (3114141443612), we get a palindrome (5277582857725).

The spelling of 2163441414113 in words is "two trillion, one hundred sixty-three billion, four hundred forty-one million, four hundred fourteen thousand, one hundred thirteen".

Divisors: 1 7 62099 434693 4976941 34838587 309063059159 2163441414113