Base | Representation |
---|---|
bin | 11111100000100101110… |
… | …110001100001111000011 |
3 | 21200000000101002200012111 |
4 | 133200211312030033003 |
5 | 240434012402330232 |
6 | 4334420245040151 |
7 | 312303054255022 |
oct | 37404566141703 |
9 | 7600011080174 |
10 | 2165298480067 |
11 | 7653305a7498 |
12 | 2ab7960b6057 |
13 | 1292574478a8 |
14 | 76b2dd608b9 |
15 | 3b4cebd0047 |
hex | 1f825d8c3c3 |
2165298480067 has 2 divisors, whose sum is σ = 2165298480068. Its totient is φ = 2165298480066.
The previous prime is 2165298480029. The next prime is 2165298480083. The reversal of 2165298480067 is 7600848925612.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2165298480067 is a prime.
It is a super-4 number, since 4×21652984800674 (a number of 50 digits) contains 4444 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2165298479993 and 2165298480020.
It is not a weakly prime, because it can be changed into another prime (2165298490067) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1082649240033 + 1082649240034.
It is an arithmetic number, because the mean of its divisors is an integer number (1082649240034).
Almost surely, 22165298480067 is an apocalyptic number.
2165298480067 is a deficient number, since it is larger than the sum of its proper divisors (1).
2165298480067 is an equidigital number, since it uses as much as digits as its factorization.
2165298480067 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 11612160, while the sum is 58.
The spelling of 2165298480067 in words is "two trillion, one hundred sixty-five billion, two hundred ninety-eight million, four hundred eighty thousand, sixty-seven".
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