Base | Representation |
---|---|
bin | 1001110110011001100100… |
… | …11000100001101101001001 |
3 | 2211200201012002211012121202 |
4 | 10323030302120201231021 |
5 | 10314340412013122131 |
6 | 114022345014113545 |
7 | 4363624021530635 |
oct | 473146230415511 |
9 | 84621162735552 |
10 | 21660365364041 |
11 | 69a1122621a38 |
12 | 2519b1064b8b5 |
13 | c1174356c3a1 |
14 | 54c51db47dc5 |
15 | 278680cddbcb |
hex | 13b332621b49 |
21660365364041 has 4 divisors (see below), whose sum is σ = 21668764112400. Its totient is φ = 21651966615684.
The previous prime is 21660365364019. The next prime is 21660365364047. The reversal of 21660365364041 is 14046356306612.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 21660365364041 - 230 = 21659291622217 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (21660365364047) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4199370311 + ... + 4199375468.
It is an arithmetic number, because the mean of its divisors is an integer number (5417191028100).
Almost surely, 221660365364041 is an apocalyptic number.
It is an amenable number.
21660365364041 is a deficient number, since it is larger than the sum of its proper divisors (8398748359).
21660365364041 is an equidigital number, since it uses as much as digits as its factorization.
21660365364041 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8398748358.
The product of its (nonzero) digits is 1866240, while the sum is 47.
The spelling of 21660365364041 in words is "twenty-one trillion, six hundred sixty billion, three hundred sixty-five million, three hundred sixty-four thousand, forty-one".
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