Base | Representation |
---|---|
bin | 11111101001000101110… |
… | …110110001111111110001 |
3 | 21200212120110002021211111 |
4 | 133221011312301333301 |
5 | 241111210403041431 |
6 | 4342530043313321 |
7 | 313045201166245 |
oct | 37510566617761 |
9 | 7625513067744 |
10 | 2174425440241 |
11 | 76919452378a |
12 | 2b150281b841 |
13 | 12a0802bab42 |
14 | 77358184425 |
15 | 3b8660d97b1 |
hex | 1fa45db1ff1 |
2174425440241 has 2 divisors, whose sum is σ = 2174425440242. Its totient is φ = 2174425440240.
The previous prime is 2174425440227. The next prime is 2174425440251. The reversal of 2174425440241 is 1420445244712.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1323871155216 + 850554285025 = 1150596^2 + 922255^2 .
It is a cyclic number.
It is not a de Polignac number, because 2174425440241 - 231 = 2172277956593 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2174425440194 and 2174425440203.
It is not a weakly prime, because it can be changed into another prime (2174425440221) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1087212720120 + 1087212720121.
It is an arithmetic number, because the mean of its divisors is an integer number (1087212720121).
Almost surely, 22174425440241 is an apocalyptic number.
It is an amenable number.
2174425440241 is a deficient number, since it is larger than the sum of its proper divisors (1).
2174425440241 is an equidigital number, since it uses as much as digits as its factorization.
2174425440241 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 286720, while the sum is 40.
The spelling of 2174425440241 in words is "two trillion, one hundred seventy-four billion, four hundred twenty-five million, four hundred forty thousand, two hundred forty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.092 sec. • engine limits •