2175081131 has 2 divisors, whose sum is σ = 2175081132. Its totient is φ = 2175081130.

The previous prime is 2175081091. The next prime is 2175081143. The reversal of 2175081131 is 1311805712.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2175081131 - 2¹⁰ = 2175080107 is a prime.

It is a super-2 number, since 2×2175081131² = 9461955852864478322, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2175081094 and 2175081103.

It is not a weakly prime, because it can be changed into another prime (2175081431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1087540565 + 1087540566.

It is an arithmetic number, because the mean of its divisors is an integer number (1087540566).

Almost surely, 2^2175081131 is an apocalyptic number.

2175081131 is a deficient number, since it is larger than the sum of its proper divisors (1).

2175081131 is an equidigital number, since it uses as much as digits as its factorization.

2175081131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1680, while the sum is 29.

The square root of 2175081131 is about 46637.7650729535. The cubic root of 2175081131 is about 1295.6622941654.

Adding to 2175081131 its reverse (1311805712), we get a palindrome (3486886843).

The spelling of 2175081131 in words is "two billion, one hundred seventy-five million, eighty-one thousand, one hundred thirty-one".