Base | Representation |
---|---|
bin | 11111110011000000001… |
… | …000101111011110010001 |
3 | 21201220001001212122001011 |
4 | 133303000020233132101 |
5 | 241300004111402231 |
6 | 4351450023010521 |
7 | 313602665141302 |
oct | 37630010573621 |
9 | 7656031778034 |
10 | 2185066903441 |
11 | 772755336574 |
12 | 2b3592599a41 |
13 | 12b087b60726 |
14 | 77a875a47a9 |
15 | 3bc8a4559b1 |
hex | 1fcc022f791 |
2185066903441 has 2 divisors, whose sum is σ = 2185066903442. Its totient is φ = 2185066903440.
The previous prime is 2185066903381. The next prime is 2185066903463. The reversal of 2185066903441 is 1443096605812.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2087288115025 + 97778788416 = 1444745^2 + 312696^2 .
It is a cyclic number.
It is not a de Polignac number, because 2185066903441 - 221 = 2185064806289 is a prime.
It is not a weakly prime, because it can be changed into another prime (2185066900441) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1092533451720 + 1092533451721.
It is an arithmetic number, because the mean of its divisors is an integer number (1092533451721).
Almost surely, 22185066903441 is an apocalyptic number.
It is an amenable number.
2185066903441 is a deficient number, since it is larger than the sum of its proper divisors (1).
2185066903441 is an equidigital number, since it uses as much as digits as its factorization.
2185066903441 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1244160, while the sum is 49.
The spelling of 2185066903441 in words is "two trillion, one hundred eighty-five billion, sixty-six million, nine hundred three thousand, four hundred forty-one".
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