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2197933406593 = 2639983258207
BaseRepresentation
bin11111111110111111000…
…010100011100110000001
321210010020202110201020221
4133332333002203212001
5242002331423002333
64401414444503041
7314536560462301
oct37767702434601
97703222421227
102197933406593
11778158120851
122b5b8354aa81
1312c3586910c2
14785482dd601
153c28ecd7d2d
hex1ffbf0a3981

2197933406593 has 4 divisors (see below), whose sum is σ = 2198016691200. Its totient is φ = 2197850121988.

The previous prime is 2197933406551. The next prime is 2197933406611. The reversal of 2197933406593 is 3956043397912.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2197933406593 is a prime.

It is a super-2 number, since 2×21979334065932 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2197933436593) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 41602705 + ... + 41655502.

It is an arithmetic number, because the mean of its divisors is an integer number (549504172800).

Almost surely, 22197933406593 is an apocalyptic number.

It is an amenable number.

2197933406593 is a deficient number, since it is larger than the sum of its proper divisors (83284607).

2197933406593 is an equidigital number, since it uses as much as digits as its factorization.

2197933406593 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 83284606.

The product of its (nonzero) digits is 33067440, while the sum is 61.

The spelling of 2197933406593 in words is "two trillion, one hundred ninety-seven billion, nine hundred thirty-three million, four hundred six thousand, five hundred ninety-three".

Divisors: 1 26399 83258207 2197933406593