Base | Representation |
---|---|
bin | 11111111110111111000… |
… | …010100011100110000001 |
3 | 21210010020202110201020221 |
4 | 133332333002203212001 |
5 | 242002331423002333 |
6 | 4401414444503041 |
7 | 314536560462301 |
oct | 37767702434601 |
9 | 7703222421227 |
10 | 2197933406593 |
11 | 778158120851 |
12 | 2b5b8354aa81 |
13 | 12c3586910c2 |
14 | 785482dd601 |
15 | 3c28ecd7d2d |
hex | 1ffbf0a3981 |
2197933406593 has 4 divisors (see below), whose sum is σ = 2198016691200. Its totient is φ = 2197850121988.
The previous prime is 2197933406551. The next prime is 2197933406611. The reversal of 2197933406593 is 3956043397912.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2197933406593 is a prime.
It is a super-2 number, since 2×21979334065932 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2197933436593) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 41602705 + ... + 41655502.
It is an arithmetic number, because the mean of its divisors is an integer number (549504172800).
Almost surely, 22197933406593 is an apocalyptic number.
It is an amenable number.
2197933406593 is a deficient number, since it is larger than the sum of its proper divisors (83284607).
2197933406593 is an equidigital number, since it uses as much as digits as its factorization.
2197933406593 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 83284606.
The product of its (nonzero) digits is 33067440, while the sum is 61.
The spelling of 2197933406593 in words is "two trillion, one hundred ninety-seven billion, nine hundred thirty-three million, four hundred six thousand, five hundred ninety-three".
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