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2200101111113 = 6012833659011
BaseRepresentation
bin100000000001000000001…
…111101100010101001001
321210022211211101111211112
4200001000033230111021
5242021301341023423
64402413522140105
7314644361612453
oct40010017542511
97708754344745
102200101111113
1177906a7a2294
122b64894b1635
1312c6127c59b9
14786b21712d3
153c36a275a78
hex200403ec549

2200101111113 has 4 divisors (see below), whose sum is σ = 2200105371408. Its totient is φ = 2200096850820.

The previous prime is 2200101111079. The next prime is 2200101111167. The reversal of 2200101111113 is 3111111010022.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2200101111113 - 210 = 2200101110089 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2200101111613) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1228223 + ... + 2430788.

It is an arithmetic number, because the mean of its divisors is an integer number (550026342852).

Almost surely, 22200101111113 is an apocalyptic number.

It is an amenable number.

2200101111113 is a deficient number, since it is larger than the sum of its proper divisors (4260295).

2200101111113 is an equidigital number, since it uses as much as digits as its factorization.

2200101111113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4260294.

The product of its (nonzero) digits is 12, while the sum is 14.

Adding to 2200101111113 its reverse (3111111010022), we get a palindrome (5311212121135).

The spelling of 2200101111113 in words is "two trillion, two hundred billion, one hundred one million, one hundred eleven thousand, one hundred thirteen".

Divisors: 1 601283 3659011 2200101111113