Base | Representation |
---|---|
bin | 100000000001001100110… |
… | …001101010100100110011 |
3 | 21210100101110222102022221 |
4 | 200001030301222210303 |
5 | 242022214200442121 |
6 | 4402450432141511 |
7 | 314652523554556 |
oct | 40011461524463 |
9 | 7710343872287 |
10 | 2200311343411 |
11 | 779168433995 |
12 | 2b6527997897 |
13 | 12c6472234cc |
14 | 786d205869d |
15 | 3c37d951b41 |
hex | 2004cc6a933 |
2200311343411 has 2 divisors, whose sum is σ = 2200311343412. Its totient is φ = 2200311343410.
The previous prime is 2200311343397. The next prime is 2200311343441. The reversal of 2200311343411 is 1143431130022.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2200311343411 - 25 = 2200311343379 is a prime.
It is a super-2 number, since 2×22003113434112 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2200311343441) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1100155671705 + 1100155671706.
It is an arithmetic number, because the mean of its divisors is an integer number (1100155671706).
Almost surely, 22200311343411 is an apocalyptic number.
2200311343411 is a deficient number, since it is larger than the sum of its proper divisors (1).
2200311343411 is an equidigital number, since it uses as much as digits as its factorization.
2200311343411 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 2200311343411 its reverse (1143431130022), we get a palindrome (3343742473433).
The spelling of 2200311343411 in words is "two trillion, two hundred billion, three hundred eleven million, three hundred forty-three thousand, four hundred eleven".
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