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22011100112017 is a prime number
BaseRepresentation
bin1010000000100110110111…
…10011011010010010010001
32212221020111102010110201201
411000103123303122102101
510341112213112041032
6114451432041031201
74431151402642402
oct500233363322221
985836442113651
1022011100112017
117016945204315
122575a94a85501
13c3883a425213
145614b2ddb9a9
1528285c5ca8e7
hex1404dbcda491

22011100112017 has 2 divisors, whose sum is σ = 22011100112018. Its totient is φ = 22011100112016.

The previous prime is 22011100112011. The next prime is 22011100112143. The reversal of 22011100112017 is 71021100111022.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 21845144906641 + 165955205376 = 4673879^2 + 407376^2 .

It is a cyclic number.

It is not a de Polignac number, because 22011100112017 - 23 = 22011100112009 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 22011100111985 and 22011100112003.

It is not a weakly prime, because it can be changed into another prime (22011100112011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11005550056008 + 11005550056009.

It is an arithmetic number, because the mean of its divisors is an integer number (11005550056009).

Almost surely, 222011100112017 is an apocalyptic number.

It is an amenable number.

22011100112017 is a deficient number, since it is larger than the sum of its proper divisors (1).

22011100112017 is an equidigital number, since it uses as much as digits as its factorization.

22011100112017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 56, while the sum is 19.

Adding to 22011100112017 its reverse (71021100111022), we get a palindrome (93032200223039).

The spelling of 22011100112017 in words is "twenty-two trillion, eleven billion, one hundred million, one hundred twelve thousand, seventeen".