Base | Representation |
---|---|
bin | 100000000010001010101… |
… | …011111001101101111011 |
3 | 21210110001212102122200212 |
4 | 200002022223321231323 |
5 | 242031331101114323 |
6 | 4403141454421335 |
7 | 315020335302233 |
oct | 40021253715573 |
9 | 7713055378625 |
10 | 2201350019963 |
11 | 779650773a66 |
12 | 2b677780184b |
13 | 12c781482a13 |
14 | 7878dd92cc3 |
15 | 3c3dec22b78 |
hex | 2008aaf9b7b |
2201350019963 has 2 divisors, whose sum is σ = 2201350019964. Its totient is φ = 2201350019962.
The previous prime is 2201350019927. The next prime is 2201350020073. The reversal of 2201350019963 is 3699100531022.
2201350019963 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2201350019963 - 26 = 2201350019899 is a prime.
It is a super-2 number, since 2×22013500199632 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 2201350019963.
It is not a weakly prime, because it can be changed into another prime (2201350019263) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1100675009981 + 1100675009982.
It is an arithmetic number, because the mean of its divisors is an integer number (1100675009982).
Almost surely, 22201350019963 is an apocalyptic number.
2201350019963 is a deficient number, since it is larger than the sum of its proper divisors (1).
2201350019963 is an equidigital number, since it uses as much as digits as its factorization.
2201350019963 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 87480, while the sum is 41.
The spelling of 2201350019963 in words is "two trillion, two hundred one billion, three hundred fifty million, nineteen thousand, nine hundred sixty-three".
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