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22014401115 = 357503416821
BaseRepresentation
bin10100100000001010…
…010001101001011011
32002211012222110002110
4110200022101221123
5330041141313430
614040245003403
71406352215310
oct244012215133
962735873073
1022014401115
119377612433
1243246b3563
1320cab24b65
1410cba4cd07
1588ca257b0
hex520291a5b

22014401115 has 32 divisors (see below), whose sum is σ = 40335031296. Its totient is φ = 10043694720.

The previous prime is 22014401093. The next prime is 22014401153. The reversal of 22014401115 is 51110441022.

It is not a de Polignac number, because 22014401115 - 214 = 22014384731 is a prime.

It is a super-2 number, since 2×220144011152 (a number of 21 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (21).

It is a junction number, because it is equal to n+sod(n) for n = 22014401091 and 22014401100.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 155596 + ... + 261225.

It is an arithmetic number, because the mean of its divisors is an integer number (1260469728).

Almost surely, 222014401115 is an apocalyptic number.

22014401115 is a deficient number, since it is larger than the sum of its proper divisors (18320630181).

22014401115 is a wasteful number, since it uses less digits than its factorization.

22014401115 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 417339.

The product of its (nonzero) digits is 320, while the sum is 21.

Adding to 22014401115 its reverse (51110441022), we get a palindrome (73124842137).

The spelling of 22014401115 in words is "twenty-two billion, fourteen million, four hundred one thousand, one hundred fifteen".

Divisors: 1 3 5 7 15 21 35 105 503 1509 2515 3521 7545 10563 17605 52815 416821 1250463 2084105 2917747 6252315 8753241 14588735 43766205 209660963 628982889 1048304815 1467626741 3144914445 4402880223 7338133705 22014401115