Base | Representation |
---|---|
bin | 1010000001000001100000… |
… | …10101001001010010110001 |
3 | 2212222121102012210202010202 |
4 | 11000200300111021102301 |
5 | 10341331011201041340 |
6 | 114502155220404545 |
7 | 4432166010464240 |
oct | 500406025112261 |
9 | 85877365722122 |
10 | 22025403143345 |
11 | 7021a14967468 |
12 | 2578806b46755 |
13 | c39ca9753874 |
14 | 56206c836957 |
15 | 282de811ac15 |
hex | 1408305494b1 |
22025403143345 has 16 divisors (see below), whose sum is σ = 30473579272320. Its totient is φ = 14969477531904.
The previous prime is 22025403143333. The next prime is 22025403143389. The reversal of 22025403143345 is 54334130452022.
It is not a de Polignac number, because 22025403143345 - 222 = 22025398949041 is a prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 22025403143299 and 22025403143308.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2784497075 + ... + 2784504984.
It is an arithmetic number, because the mean of its divisors is an integer number (1904598704520).
Almost surely, 222025403143345 is an apocalyptic number.
It is an amenable number.
22025403143345 is a deficient number, since it is larger than the sum of its proper divisors (8448176128975).
22025403143345 is a wasteful number, since it uses less digits than its factorization.
22025403143345 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5569002184.
The product of its (nonzero) digits is 345600, while the sum is 38.
Adding to 22025403143345 its reverse (54334130452022), we get a palindrome (76359533595367).
The spelling of 22025403143345 in words is "twenty-two trillion, twenty-five billion, four hundred three million, one hundred forty-three thousand, three hundred forty-five".
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