Base | Representation |
---|---|
bin | 100000000100110110111… |
… | …100011000001010011011 |
3 | 21210201112021110212121211 |
4 | 200010312330120022123 |
5 | 242103240421120443 |
6 | 4404340333243551 |
7 | 315152060013541 |
oct | 40046674301233 |
9 | 7721467425554 |
10 | 2204240020123 |
11 | 77a8a4032949 |
12 | 2b72436335b7 |
13 | 12cb22131c9b |
14 | 78985b23d91 |
15 | 3c50d7d919d |
hex | 20136f1829b |
2204240020123 has 4 divisors (see below), whose sum is σ = 2212197565600. Its totient is φ = 2196282474648.
The previous prime is 2204240020061. The next prime is 2204240020127. The reversal of 2204240020123 is 3210200424022.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2204240020123 - 213 = 2204240011931 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2204240020094 and 2204240020103.
It is not an unprimeable number, because it can be changed into a prime (2204240020127) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3978772323 + ... + 3978772876.
It is an arithmetic number, because the mean of its divisors is an integer number (553049391400).
Almost surely, 22204240020123 is an apocalyptic number.
2204240020123 is a deficient number, since it is larger than the sum of its proper divisors (7957545477).
2204240020123 is an equidigital number, since it uses as much as digits as its factorization.
2204240020123 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7957545476.
The product of its (nonzero) digits is 1536, while the sum is 22.
Adding to 2204240020123 its reverse (3210200424022), we get a palindrome (5414440444145).
The spelling of 2204240020123 in words is "two trillion, two hundred four billion, two hundred forty million, twenty thousand, one hundred twenty-three".
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