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22044411443993 is a prime number
BaseRepresentation
bin1010000001100100111010…
…10100000011101100011001
32220001102110221021110121212
411000302131110003230121
510342133423312201433
6114515021322312505
74433441031411341
oct500623524035431
986042427243555
1022044411443993
117029a89622044
122580430958735
13c3ba18839543
14562d53131d21
1528365bc94d48
hex140c9d503b19

22044411443993 has 2 divisors, whose sum is σ = 22044411443994. Its totient is φ = 22044411443992.

The previous prime is 22044411443969. The next prime is 22044411444037. The reversal of 22044411443993 is 39934411444022.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 19997460309904 + 2046951134089 = 4471852^2 + 1430717^2 .

It is a cyclic number.

It is not a de Polignac number, because 22044411443993 - 28 = 22044411443737 is a prime.

It is a super-3 number, since 3×220444114439933 (a number of 41 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (22044411442993) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11022205721996 + 11022205721997.

It is an arithmetic number, because the mean of its divisors is an integer number (11022205721997).

Almost surely, 222044411443993 is an apocalyptic number.

It is an amenable number.

22044411443993 is a deficient number, since it is larger than the sum of its proper divisors (1).

22044411443993 is an equidigital number, since it uses as much as digits as its factorization.

22044411443993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2985984, while the sum is 50.

The spelling of 22044411443993 in words is "twenty-two trillion, forty-four billion, four hundred eleven million, four hundred forty-three thousand, nine hundred ninety-three".