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2210014113 = 31129652499
BaseRepresentation
bin1000001110111010…
…0010001110100001
312201000112100102120
42003232202032201
514011230422423
61003144134453
7105523544556
oct20356421641
95630470376
102210014113
11a3454a34a
12518167429
13292b29778
1416d726a2d
15ce048ee3
hex83ba23a1

2210014113 has 8 divisors (see below), whose sum is σ = 2949300000. Its totient is φ = 1472035488.

The previous prime is 2210014099. The next prime is 2210014123. The reversal of 2210014113 is 3114100122.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 2210014113 - 212 = 2210010017 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2210014092 and 2210014101.

It is not an unprimeable number, because it can be changed into a prime (2210014123) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 322863 + ... + 329636.

It is an arithmetic number, because the mean of its divisors is an integer number (368662500).

Almost surely, 22210014113 is an apocalyptic number.

It is an amenable number.

2210014113 is a deficient number, since it is larger than the sum of its proper divisors (739285887).

2210014113 is a wasteful number, since it uses less digits than its factorization.

2210014113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 653631.

The product of its (nonzero) digits is 48, while the sum is 15.

The square root of 2210014113 is about 47010.7871982591. The cubic root of 2210014113 is about 1302.5618344189.

Adding to 2210014113 its reverse (3114100122), we get a palindrome (5324114235).

The spelling of 2210014113 in words is "two billion, two hundred ten million, fourteen thousand, one hundred thirteen".

Divisors: 1 3 1129 3387 652499 1957497 736671371 2210014113