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22101121113 = 37367040371
BaseRepresentation
bin10100100101010101…
…000101100001011001
32010001021011021120020
4110211111011201121
5330230341333423
614053023421053
71411454300301
oct244525054131
963037137506
1022101121113
119411563455
124349754789
132112a98b76
1410d9384601
158954554e3
hex525545859

22101121113 has 4 divisors (see below), whose sum is σ = 29468161488. Its totient is φ = 14734080740.

The previous prime is 22101121087. The next prime is 22101121117. The reversal of 22101121113 is 31112110122.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 22101121113 - 228 = 21832685657 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 22101121092 and 22101121101.

It is not an unprimeable number, because it can be changed into a prime (22101121117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3683520183 + ... + 3683520188.

It is an arithmetic number, because the mean of its divisors is an integer number (7367040372).

Almost surely, 222101121113 is an apocalyptic number.

It is an amenable number.

22101121113 is a deficient number, since it is larger than the sum of its proper divisors (7367040375).

22101121113 is an equidigital number, since it uses as much as digits as its factorization.

22101121113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7367040374.

The product of its (nonzero) digits is 24, while the sum is 15.

Adding to 22101121113 its reverse (31112110122), we get a palindrome (53213231235).

The spelling of 22101121113 in words is "twenty-two billion, one hundred one million, one hundred twenty-one thousand, one hundred thirteen".

Divisors: 1 3 7367040371 22101121113