Base | Representation |
---|---|
bin | 1100110111101100111… |
… | …1111101100110010011 |
3 | 210010201121120101210101 |
4 | 3031323033331212103 |
5 | 12110313421123011 |
6 | 245324350313231 |
7 | 21655224313465 |
oct | 3157317754623 |
9 | 703647511711 |
10 | 221111114131 |
11 | 85855506766 |
12 | 36a297b8817 |
13 | 17b09c6949b |
14 | a9b7b9a135 |
15 | 5b41a1e2c1 |
hex | 337b3fd993 |
221111114131 has 2 divisors, whose sum is σ = 221111114132. Its totient is φ = 221111114130.
The previous prime is 221111114111. The next prime is 221111114179. The reversal of 221111114131 is 131411111122.
It is a m-pointer prime, because the next prime (221111114179) can be obtained adding 221111114131 to its product of digits (48).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 221111114131 - 211 = 221111112083 is a prime.
It is a super-2 number, since 2×2211111141312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 221111114099 and 221111114108.
It is not a weakly prime, because it can be changed into another prime (221111114101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 110555557065 + 110555557066.
It is an arithmetic number, because the mean of its divisors is an integer number (110555557066).
Almost surely, 2221111114131 is an apocalyptic number.
221111114131 is a deficient number, since it is larger than the sum of its proper divisors (1).
221111114131 is an equidigital number, since it uses as much as digits as its factorization.
221111114131 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 48, while the sum is 19.
Adding to 221111114131 its reverse (131411111122), we get a palindrome (352522225253).
The spelling of 221111114131 in words is "two hundred twenty-one billion, one hundred eleven million, one hundred fourteen thousand, one hundred thirty-one".
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