Base | Representation |
---|---|
bin | 100000001011011011011… |
… | …010011111001011011001 |
3 | 21211101201220102122121201 |
4 | 200023123122133023121 |
5 | 242212212323001042 |
6 | 4411504332034201 |
7 | 315521635536262 |
oct | 40133332371331 |
9 | 7741656378551 |
10 | 2211294343897 |
11 | 7828940107a1 |
12 | 2b8692002961 |
13 | 1306a7778372 |
14 | 79054981969 |
15 | 3c7c2c841b7 |
hex | 202db69f2d9 |
2211294343897 has 2 divisors, whose sum is σ = 2211294343898. Its totient is φ = 2211294343896.
The previous prime is 2211294343877. The next prime is 2211294343927. The reversal of 2211294343897 is 7983434921122.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2065052346841 + 146241997056 = 1437029^2 + 382416^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2211294343897 is a prime.
It is a super-2 number, since 2×22112943438972 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2211294343877) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1105647171948 + 1105647171949.
It is an arithmetic number, because the mean of its divisors is an integer number (1105647171949).
Almost surely, 22211294343897 is an apocalyptic number.
It is an amenable number.
2211294343897 is a deficient number, since it is larger than the sum of its proper divisors (1).
2211294343897 is an equidigital number, since it uses as much as digits as its factorization.
2211294343897 is an evil number, because the sum of its binary digits is even.
The product of its digits is 5225472, while the sum is 55.
The spelling of 2211294343897 in words is "two trillion, two hundred eleven billion, two hundred ninety-four million, three hundred forty-three thousand, eight hundred ninety-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.636 sec. • engine limits •