Base | Representation |
---|---|
bin | 1010000011100100101100… |
… | …01011000011011111111011 |
3 | 2220021222112202200002021102 |
4 | 11001302112023003133323 |
5 | 10344244421321320443 |
6 | 115010324351402015 |
7 | 4441420013136200 |
oct | 501622613033773 |
9 | 86258482602242 |
10 | 22113011120123 |
11 | 7056091324060 |
12 | 259179682330b |
13 | c4532bb20b91 |
14 | 5663bdb8dca7 |
15 | 285324499cb8 |
hex | 141c962c37fb |
22113011120123 has 48 divisors (see below), whose sum is σ = 28815852675456. Its totient is φ = 16770723096960.
The previous prime is 22113011120087. The next prime is 22113011120149. The reversal of 22113011120123 is 32102111031122.
It is not a de Polignac number, because 22113011120123 - 214 = 22113011103739 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 22113011120095 and 22113011120104.
It is not an unprimeable number, because it can be changed into a prime (22113011120023) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 4873415 + ... + 8244767.
It is an arithmetic number, because the mean of its divisors is an integer number (600330264072).
Almost surely, 222113011120123 is an apocalyptic number.
22113011120123 is a deficient number, since it is larger than the sum of its proper divisors (6702841555333).
22113011120123 is a wasteful number, since it uses less digits than its factorization.
22113011120123 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3371704 (or 3371697 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 20.
Adding to 22113011120123 its reverse (32102111031122), we get a palindrome (54215122151245).
The spelling of 22113011120123 in words is "twenty-two trillion, one hundred thirteen billion, eleven million, one hundred twenty thousand, one hundred twenty-three".
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