Base | Representation |
---|---|
bin | 1010000011110010000111… |
… | …10111100110001001000001 |
3 | 2220022200011011212101221021 |
4 | 11001321003313212021001 |
5 | 10344404202334101032 |
6 | 115013515555425441 |
7 | 4442063451402031 |
oct | 501710367461101 |
9 | 86280134771837 |
10 | 22120220222017 |
11 | 7059150708005 |
12 | 2593068bb5281 |
13 | c45c0a549c48 |
14 | 5668a53bb8c1 |
15 | 2855e731a097 |
hex | 141e43de6241 |
22120220222017 has 2 divisors, whose sum is σ = 22120220222018. Its totient is φ = 22120220222016.
The previous prime is 22120220221817. The next prime is 22120220222029. The reversal of 22120220222017 is 71022202202122.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 14244653575681 + 7875566646336 = 3774209^2 + 2806344^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-22120220222017 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 22120220221982 and 22120220222000.
It is not a weakly prime, because it can be changed into another prime (22120220222057) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11060110111008 + 11060110111009.
It is an arithmetic number, because the mean of its divisors is an integer number (11060110111009).
Almost surely, 222120220222017 is an apocalyptic number.
It is an amenable number.
22120220222017 is a deficient number, since it is larger than the sum of its proper divisors (1).
22120220222017 is an equidigital number, since it uses as much as digits as its factorization.
22120220222017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1792, while the sum is 25.
Adding to 22120220222017 its reverse (71022202202122), we get a palindrome (93142422424139).
The spelling of 22120220222017 in words is "twenty-two trillion, one hundred twenty billion, two hundred twenty million, two hundred twenty-two thousand, seventeen".
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