Base | Representation |
---|---|
bin | 100000001100001001010… |
… | …111100110111010111001 |
3 | 21211110201122012100222011 |
4 | 200030021113212322321 |
5 | 242220302211403423 |
6 | 4412113033125521 |
7 | 315550020106465 |
oct | 40141127467271 |
9 | 7743648170864 |
10 | 2212065341113 |
11 | 78314a242381 |
12 | 2b88682598a1 |
13 | 13079b415134 |
14 | 790c911b4a5 |
15 | 3c81a7ccb0d |
hex | 203095e6eb9 |
2212065341113 has 2 divisors, whose sum is σ = 2212065341114. Its totient is φ = 2212065341112.
The previous prime is 2212065341063. The next prime is 2212065341147. The reversal of 2212065341113 is 3111435602122.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2210847819664 + 1217521449 = 1486892^2 + 34893^2 .
It is a cyclic number.
It is not a de Polignac number, because 2212065341113 - 241 = 13042085561 is a prime.
It is not a weakly prime, because it can be changed into another prime (2212065341153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1106032670556 + 1106032670557.
It is an arithmetic number, because the mean of its divisors is an integer number (1106032670557).
Almost surely, 22212065341113 is an apocalyptic number.
It is an amenable number.
2212065341113 is a deficient number, since it is larger than the sum of its proper divisors (1).
2212065341113 is an equidigital number, since it uses as much as digits as its factorization.
2212065341113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8640, while the sum is 31.
The spelling of 2212065341113 in words is "two trillion, two hundred twelve billion, sixty-five million, three hundred forty-one thousand, one hundred thirteen".
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