Base | Representation |
---|---|
bin | 100000001100001101011… |
… | …010001011000000000011 |
3 | 21211110220100201222221021 |
4 | 200030031122023000003 |
5 | 242220422034401201 |
6 | 4412123454010311 |
7 | 315551502201526 |
oct | 40141532130003 |
9 | 7743810658837 |
10 | 2212133122051 |
11 | 783184528186 |
12 | 2b8886aa6997 |
13 | 1307ac4878b8 |
14 | 790d4122bbd |
15 | 3c82171aea1 |
hex | 2030d68b003 |
2212133122051 has 2 divisors, whose sum is σ = 2212133122052. Its totient is φ = 2212133122050.
The previous prime is 2212133122021. The next prime is 2212133122063. The reversal of 2212133122051 is 1502213312122.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2212133122051 - 211 = 2212133120003 is a prime.
It is not a weakly prime, because it can be changed into another prime (2212133122021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1106066561025 + 1106066561026.
It is an arithmetic number, because the mean of its divisors is an integer number (1106066561026).
Almost surely, 22212133122051 is an apocalyptic number.
2212133122051 is a deficient number, since it is larger than the sum of its proper divisors (1).
2212133122051 is an equidigital number, since it uses as much as digits as its factorization.
2212133122051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 2212133122051 its reverse (1502213312122), we get a palindrome (3714346434173).
The spelling of 2212133122051 in words is "two trillion, two hundred twelve billion, one hundred thirty-three million, one hundred twenty-two thousand, fifty-one".
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