Base | Representation |
---|---|
bin | 100000001100010001011… |
… | …110000000000000000001 |
3 | 21211111002002220110120002 |
4 | 200030101132000000001 |
5 | 242221042004000213 |
6 | 4412134325525345 |
7 | 315553260144101 |
oct | 40142136000001 |
9 | 7744062813502 |
10 | 2212201234433 |
11 | 783209a1a003 |
12 | 2b88a5873855 |
13 | 1307c0615198 |
14 | 790dd1b3201 |
15 | 3c8276c2658 |
hex | 20311780001 |
2212201234433 has 8 divisors (see below), whose sum is σ = 2284146571776. Its totient is φ = 2140292397600.
The previous prime is 2212201234403. The next prime is 2212201234447. The reversal of 2212201234433 is 3344321022122.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 2212201234433 - 214 = 2212201218049 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 2212201234396 and 2212201234405.
It is not an unprimeable number, because it can be changed into a prime (2212201234403) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 9001916 + ... + 9244397.
It is an arithmetic number, because the mean of its divisors is an integer number (285518321472).
Almost surely, 22212201234433 is an apocalyptic number.
It is an amenable number.
2212201234433 is a deficient number, since it is larger than the sum of its proper divisors (71945337343).
2212201234433 is a wasteful number, since it uses less digits than its factorization.
2212201234433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18250255.
The product of its (nonzero) digits is 13824, while the sum is 29.
Adding to 2212201234433 its reverse (3344321022122), we get a palindrome (5556522256555).
The spelling of 2212201234433 in words is "two trillion, two hundred twelve billion, two hundred one million, two hundred thirty-four thousand, four hundred thirty-three".
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