Search a number
-
+
22122101313353 is a prime number
BaseRepresentation
bin1010000011110101100111…
…11111011000111101001001
32220022212000021110202010202
411001322303333120331021
510344422030414011403
6115014430354021545
74442161202406236
oct501726377307511
986285007422122
1022122101313353
117059a26518848
1225934b2b778b5
13c4614a190042
14566a0316278d
152856a7540688
hex141eb3fd8f49

22122101313353 has 2 divisors, whose sum is σ = 22122101313354. Its totient is φ = 22122101313352.

The previous prime is 22122101313287. The next prime is 22122101313407. The reversal of 22122101313353 is 35331310122122.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 20297475793984 + 1824625519369 = 4505272^2 + 1350787^2 .

It is a cyclic number.

It is not a de Polignac number, because 22122101313353 - 210 = 22122101312329 is a prime.

It is a super-3 number, since 3×221221013133533 (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (22122101313253) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11061050656676 + 11061050656677.

It is an arithmetic number, because the mean of its divisors is an integer number (11061050656677).

Almost surely, 222122101313353 is an apocalyptic number.

It is an amenable number.

22122101313353 is a deficient number, since it is larger than the sum of its proper divisors (1).

22122101313353 is an equidigital number, since it uses as much as digits as its factorization.

22122101313353 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6480, while the sum is 29.

Adding to 22122101313353 its reverse (35331310122122), we get a palindrome (57453411435475).

The spelling of 22122101313353 in words is "twenty-two trillion, one hundred twenty-two billion, one hundred one million, three hundred thirteen thousand, three hundred fifty-three".