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2213003110147 is a prime number
BaseRepresentation
bin100000001101000001010…
…000111010011100000011
321211120010222202222020121
4200031001100322130003
5242224212244011042
64412350052521111
7315612165032134
oct40150120723403
97746128688217
102213003110147
11783590621105
122b8a8a320197
131308ba7a3a5b
14791778a9c8b
153c872cba367
hex2034143a703

2213003110147 has 2 divisors, whose sum is σ = 2213003110148. Its totient is φ = 2213003110146.

The previous prime is 2213003110103. The next prime is 2213003110181. The reversal of 2213003110147 is 7410113003122.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2213003110147 - 215 = 2213003077379 is a prime.

It is not a weakly prime, because it can be changed into another prime (2213003110547) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1106501555073 + 1106501555074.

It is an arithmetic number, because the mean of its divisors is an integer number (1106501555074).

Almost surely, 22213003110147 is an apocalyptic number.

2213003110147 is a deficient number, since it is larger than the sum of its proper divisors (1).

2213003110147 is an equidigital number, since it uses as much as digits as its factorization.

2213003110147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1008, while the sum is 25.

Adding to 2213003110147 its reverse (7410113003122), we get a palindrome (9623116113269).

The spelling of 2213003110147 in words is "two trillion, two hundred thirteen billion, three million, one hundred ten thousand, one hundred forty-seven".