Base | Representation |
---|---|
bin | 100000001101111101101… |
… | …100111011100110001001 |
3 | 21211122202122202101012111 |
4 | 200031331230323212021 |
5 | 242233301333303011 |
6 | 4413034433542321 |
7 | 315646256510344 |
oct | 40157554734611 |
9 | 7748678671174 |
10 | 2214017087881 |
11 | 783a60a21635 |
12 | 2b9111a149a1 |
13 | 130a1c896191 |
14 | 7923241545b |
15 | 3c8d1d0d121 |
hex | 2037db3b989 |
2214017087881 has 2 divisors, whose sum is σ = 2214017087882. Its totient is φ = 2214017087880.
The previous prime is 2214017087833. The next prime is 2214017087903. The reversal of 2214017087881 is 1887807104122.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1238900337481 + 975116750400 = 1113059^2 + 987480^2 .
It is a cyclic number.
It is not a de Polignac number, because 2214017087881 - 231 = 2211869604233 is a prime.
It is a super-2 number, since 2×22140170878812 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2214015087881) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1107008543940 + 1107008543941.
It is an arithmetic number, because the mean of its divisors is an integer number (1107008543941).
Almost surely, 22214017087881 is an apocalyptic number.
It is an amenable number.
2214017087881 is a deficient number, since it is larger than the sum of its proper divisors (1).
2214017087881 is an equidigital number, since it uses as much as digits as its factorization.
2214017087881 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 401408, while the sum is 49.
The spelling of 2214017087881 in words is "two trillion, two hundred fourteen billion, seventeen million, eighty-seven thousand, eight hundred eighty-one".
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