Base | Representation |
---|---|
bin | 1010000100011011011111… |
… | …11000001010001000001011 |
3 | 2220101210111020212221021222 |
4 | 11002031233320022020023 |
5 | 10400240200422402103 |
6 | 115032032105152255 |
7 | 4443511066334555 |
oct | 502155770121013 |
9 | 86353436787258 |
10 | 22142433403403 |
11 | 706760a449a55 |
12 | 259742818b68b |
13 | c4803a5bcb61 |
14 | 5679b15b24d5 |
15 | 285e97508638 |
hex | 14236fe0a20b |
22142433403403 has 4 divisors (see below), whose sum is σ = 22143233056728. Its totient is φ = 22141633750080.
The previous prime is 22142433403381. The next prime is 22142433403411. The reversal of 22142433403403 is 30430433424122.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 22142433403403 - 210 = 22142433402379 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (22142433403303) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 399785126 + ... + 399840507.
It is an arithmetic number, because the mean of its divisors is an integer number (5535808264182).
Almost surely, 222142433403403 is an apocalyptic number.
22142433403403 is a deficient number, since it is larger than the sum of its proper divisors (799653325).
22142433403403 is an equidigital number, since it uses as much as digits as its factorization.
22142433403403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 799653324.
The product of its (nonzero) digits is 165888, while the sum is 35.
Adding to 22142433403403 its reverse (30430433424122), we get a palindrome (52572866827525).
The spelling of 22142433403403 in words is "twenty-two trillion, one hundred forty-two billion, four hundred thirty-three million, four hundred three thousand, four hundred three".
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