Base | Representation |
---|---|
bin | 1100111000110111111… |
… | …1000001100100011011 |
3 | 210011112112000212021011 |
4 | 3032031333001210123 |
5 | 12111434403103201 |
6 | 245415455354351 |
7 | 21666062123503 |
oct | 3161577014433 |
9 | 704475025234 |
10 | 221425441051 |
11 | 859a6986181 |
12 | 36ab6b229b7 |
13 | 17b5a112449 |
14 | aa0781ca03 |
15 | 5b5e40d151 |
hex | 338dfc191b |
221425441051 has 2 divisors, whose sum is σ = 221425441052. Its totient is φ = 221425441050.
The previous prime is 221425441037. The next prime is 221425441057. The reversal of 221425441051 is 150144524122.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 221425441051 - 25 = 221425441019 is a prime.
It is not a weakly prime, because it can be changed into another prime (221425441057) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 110712720525 + 110712720526.
It is an arithmetic number, because the mean of its divisors is an integer number (110712720526).
Almost surely, 2221425441051 is an apocalyptic number.
221425441051 is a deficient number, since it is larger than the sum of its proper divisors (1).
221425441051 is an equidigital number, since it uses as much as digits as its factorization.
221425441051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12800, while the sum is 31.
Adding to 221425441051 its reverse (150144524122), we get a palindrome (371569965173).
The spelling of 221425441051 in words is "two hundred twenty-one billion, four hundred twenty-five million, four hundred forty-one thousand, fifty-one".
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