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221430313451 = 280927788213
BaseRepresentation
bin1100111000111001000…
…1100111000111101011
3210011112212012101221102
43032032101213013223
512111442130012301
6245420152032015
721666151415654
oct3161621470753
9704485171842
10221430313451
11859a9703956
1236ab869260b
1317b5b12a119
14aa0832a52b
155b5ea71b6b
hex338e4671eb

221430313451 has 4 divisors (see below), whose sum is σ = 221431382592. Its totient is φ = 221429244312.

The previous prime is 221430313393. The next prime is 221430313501. The reversal of 221430313451 is 154313034122.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 221430313451 - 230 = 220356571627 is a prime.

It is a super-2 number, since 2×2214303134512 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (221430313151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 113180 + ... + 675033.

It is an arithmetic number, because the mean of its divisors is an integer number (55357845648).

Almost surely, 2221430313451 is an apocalyptic number.

221430313451 is a deficient number, since it is larger than the sum of its proper divisors (1069141).

221430313451 is an equidigital number, since it uses as much as digits as its factorization.

221430313451 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1069140.

The product of its (nonzero) digits is 8640, while the sum is 29.

Adding to 221430313451 its reverse (154313034122), we get a palindrome (375743347573).

The spelling of 221430313451 in words is "two hundred twenty-one billion, four hundred thirty million, three hundred thirteen thousand, four hundred fifty-one".

Divisors: 1 280927 788213 221430313451