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221444145113 is a prime number
BaseRepresentation
bin1100111000111100011…
…0010111111111011001
3210011120211020010102012
43032033012113333121
512112004200120423
6245421404315305
721666410114342
oct3161706277731
9704524203365
10221444145113
1185a064a0884
1236b01242b35
1317b60c60a39
14aa0a0cb0c9
155b60da5078
hex338f197fd9

221444145113 has 2 divisors, whose sum is σ = 221444145114. Its totient is φ = 221444145112.

The previous prime is 221444145103. The next prime is 221444145137. The reversal of 221444145113 is 311541444122.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 122799783184 + 98644361929 = 350428^2 + 314077^2 .

It is a cyclic number.

It is not a de Polignac number, because 221444145113 - 218 = 221443882969 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 221444145113.

It is not a weakly prime, because it can be changed into another prime (221444145103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 110722072556 + 110722072557.

It is an arithmetic number, because the mean of its divisors is an integer number (110722072557).

Almost surely, 2221444145113 is an apocalyptic number.

It is an amenable number.

221444145113 is a deficient number, since it is larger than the sum of its proper divisors (1).

221444145113 is an equidigital number, since it uses as much as digits as its factorization.

221444145113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 15360, while the sum is 32.

Adding to 221444145113 its reverse (311541444122), we get a palindrome (532985589235).

The spelling of 221444145113 in words is "two hundred twenty-one billion, four hundred forty-four million, one hundred forty-five thousand, one hundred thirteen".