Base | Representation |
---|---|
bin | 100000010100011111001… |
… | …011111000011001101011 |
3 | 21212022211210102020101102 |
4 | 200110133023320121223 |
5 | 242342122423102311 |
6 | 4420153442312015 |
7 | 316314656362661 |
oct | 40243713703153 |
9 | 7768753366342 |
10 | 2221021300331 |
11 | 786a25693069 |
12 | 2ba54765860b |
13 | 131597a155a2 |
14 | 796d874ac31 |
15 | 3cb91baa43b |
hex | 2051f2f866b |
2221021300331 has 2 divisors, whose sum is σ = 2221021300332. Its totient is φ = 2221021300330.
The previous prime is 2221021300273. The next prime is 2221021300391. The reversal of 2221021300331 is 1330031201222.
2221021300331 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2221021300331 - 210 = 2221021299307 is a prime.
It is a super-2 number, since 2×22210213003312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2221021300391) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1110510650165 + 1110510650166.
It is an arithmetic number, because the mean of its divisors is an integer number (1110510650166).
Almost surely, 22221021300331 is an apocalyptic number.
2221021300331 is a deficient number, since it is larger than the sum of its proper divisors (1).
2221021300331 is an equidigital number, since it uses as much as digits as its factorization.
2221021300331 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 2221021300331 its reverse (1330031201222), we get a palindrome (3551052501553).
The spelling of 2221021300331 in words is "two trillion, two hundred twenty-one billion, twenty-one million, three hundred thousand, three hundred thirty-one".
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