Base | Representation |
---|---|
bin | 100000010100100011111… |
… | …100110000101000100001 |
3 | 21212100001100210200220021 |
4 | 200110203330300220201 |
5 | 242342303403104213 |
6 | 4420205415313441 |
7 | 316316646613012 |
oct | 40244374605041 |
9 | 7770040720807 |
10 | 2221101222433 |
11 | 786a66810795 |
12 | 2ba56a37b881 |
13 | 1315ab449382 |
14 | 797051d3009 |
15 | 3cb98be5d8d |
hex | 20523f30a21 |
2221101222433 has 2 divisors, whose sum is σ = 2221101222434. Its totient is φ = 2221101222432.
The previous prime is 2221101222421. The next prime is 2221101222437. The reversal of 2221101222433 is 3342221011222.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2178139125904 + 42962096529 = 1475852^2 + 207273^2 .
It is a cyclic number.
It is not a de Polignac number, because 2221101222433 - 29 = 2221101221921 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2221101222398 and 2221101222407.
It is not a weakly prime, because it can be changed into another prime (2221101222437) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1110550611216 + 1110550611217.
It is an arithmetic number, because the mean of its divisors is an integer number (1110550611217).
Almost surely, 22221101222433 is an apocalyptic number.
It is an amenable number.
2221101222433 is a deficient number, since it is larger than the sum of its proper divisors (1).
2221101222433 is an equidigital number, since it uses as much as digits as its factorization.
2221101222433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 2221101222433 its reverse (3342221011222), we get a palindrome (5563322233655).
The spelling of 2221101222433 in words is "two trillion, two hundred twenty-one billion, one hundred one million, two hundred twenty-two thousand, four hundred thirty-three".
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