Base | Representation |
---|---|
bin | 1010000110011011100110… |
… | …10110101101010010011011 |
3 | 2220122101000111111000220011 |
4 | 11003031303112231102123 |
5 | 10402402030033020443 |
6 | 115123404540342351 |
7 | 4451464343204632 |
oct | 503156326552233 |
9 | 86571014430804 |
10 | 22211211220123 |
11 | 70937a37636a2 |
12 | 25a88218449b7 |
13 | c5167b776c23 |
14 | 56b057b62519 |
15 | 287b7069ab9d |
hex | 1433735ad49b |
22211211220123 has 2 divisors, whose sum is σ = 22211211220124. Its totient is φ = 22211211220122.
The previous prime is 22211211220069. The next prime is 22211211220223. The reversal of 22211211220123 is 32102211211222.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-22211211220123 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 22211211220094 and 22211211220103.
It is not a weakly prime, because it can be changed into another prime (22211211220223) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11105605610061 + 11105605610062.
It is an arithmetic number, because the mean of its divisors is an integer number (11105605610062).
Almost surely, 222211211220123 is an apocalyptic number.
22211211220123 is a deficient number, since it is larger than the sum of its proper divisors (1).
22211211220123 is an equidigital number, since it uses as much as digits as its factorization.
22211211220123 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 384, while the sum is 22.
Adding to 22211211220123 its reverse (32102211211222), we get a palindrome (54313422431345).
The spelling of 22211211220123 in words is "twenty-two trillion, two hundred eleven billion, two hundred eleven million, two hundred twenty thousand, one hundred twenty-three".
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