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222131011112113 is a prime number
BaseRepresentation
bin110010100000011011101000…
…000000101100110010110001
31002010111111222002110110212211
4302200123220000230302301
5213103343302321041423
62104233324443252121
764534302350043535
oct6240335000546261
91063444862413784
10222131011112113
1164861261913844
1220ab658a21a041
1396c3b3130979c
143cbd2ac1dbbc5
151aa320d8e010d
hexca06e802ccb1

222131011112113 has 2 divisors, whose sum is σ = 222131011112114. Its totient is φ = 222131011112112.

The previous prime is 222131011112069. The next prime is 222131011112149. The reversal of 222131011112113 is 311211110131222.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 181606430156449 + 40524580955664 = 13476143^2 + 6365892^2 .

It is a cyclic number.

It is not a de Polignac number, because 222131011112113 - 225 = 222130977557681 is a prime.

It is not a weakly prime, because it can be changed into another prime (222131071112113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 111065505556056 + 111065505556057.

It is an arithmetic number, because the mean of its divisors is an integer number (111065505556057).

Almost surely, 2222131011112113 is an apocalyptic number.

It is an amenable number.

222131011112113 is a deficient number, since it is larger than the sum of its proper divisors (1).

222131011112113 is an equidigital number, since it uses as much as digits as its factorization.

222131011112113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 22.

Adding to 222131011112113 its reverse (311211110131222), we get a palindrome (533342121243335).

The spelling of 222131011112113 in words is "two hundred twenty-two trillion, one hundred thirty-one billion, eleven million, one hundred twelve thousand, one hundred thirteen".