Base | Representation |
---|---|
bin | 100000010101110010001… |
… | …101000000010111110011 |
3 | 21212110102212012222220101 |
4 | 200111302031000113303 |
5 | 242403001002312201 |
6 | 4420543555053231 |
7 | 316364331124141 |
oct | 40256215002763 |
9 | 7773385188811 |
10 | 2222414104051 |
11 | 78757a907119 |
12 | 2ba875ba1217 |
13 | 13175a4446bb |
14 | 797cb708591 |
15 | 3cc240ccd01 |
hex | 205723405f3 |
2222414104051 has 2 divisors, whose sum is σ = 2222414104052. Its totient is φ = 2222414104050.
The previous prime is 2222414104013. The next prime is 2222414104061. The reversal of 2222414104051 is 1504014142222.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2222414104051 - 211 = 2222414102003 is a prime.
It is a super-2 number, since 2×22224141040512 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2222414104061) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1111207052025 + 1111207052026.
It is an arithmetic number, because the mean of its divisors is an integer number (1111207052026).
Almost surely, 22222414104051 is an apocalyptic number.
2222414104051 is a deficient number, since it is larger than the sum of its proper divisors (1).
2222414104051 is an equidigital number, since it uses as much as digits as its factorization.
2222414104051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5120, while the sum is 28.
Adding to 2222414104051 its reverse (1504014142222), we get a palindrome (3726428246273).
The spelling of 2222414104051 in words is "two trillion, two hundred twenty-two billion, four hundred fourteen million, one hundred four thousand, fifty-one".
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