Base | Representation |
---|---|
bin | 110010100100100010011000… |
… | …011010010110011011001011 |
3 | 1002011111111012101022210022112 |
4 | 302210202120122112123023 |
5 | 213123004104214003431 |
6 | 2105011104303412535 |
7 | 64563551014553066 |
oct | 6244423032263313 |
9 | 1064444171283275 |
10 | 222413143500491 |
11 | 6495a980230a69 |
12 | 20b411a78b414b |
13 | 971461447b728 |
14 | 3cccbd43358dd |
15 | 1aaa722646c2b |
hex | ca48986966cb |
222413143500491 has 2 divisors, whose sum is σ = 222413143500492. Its totient is φ = 222413143500490.
The previous prime is 222413143500469. The next prime is 222413143500503. The reversal of 222413143500491 is 194005341314222.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 222413143500491 - 218 = 222413143238347 is a prime.
It is not a weakly prime, because it can be changed into another prime (222413143700491) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 111206571750245 + 111206571750246.
It is an arithmetic number, because the mean of its divisors is an integer number (111206571750246).
Almost surely, 2222413143500491 is an apocalyptic number.
222413143500491 is a deficient number, since it is larger than the sum of its proper divisors (1).
222413143500491 is an equidigital number, since it uses as much as digits as its factorization.
222413143500491 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 207360, while the sum is 41.
The spelling of 222413143500491 in words is "two hundred twenty-two trillion, four hundred thirteen billion, one hundred forty-three million, five hundred thousand, four hundred ninety-one".
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